56=2w+3w^2

Solution for 56=2w+3w^2 equation:

56=2w+3w^2

We move all terms to the left:

56-(2w+3w^2)=0

We get rid of parentheses

-3w^2-2w+56=0

a = -3; b = -2; c = +56;
Δ = b2-4ac
Δ = -22-4·(-3)·56
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-26}{2*-3}=\frac{-24}{-6}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+26}{2*-3}=\frac{28}{-6}
=-4+2/3
$